Take 10 minutes to prepare this exercise.
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A detailed solution is then proposed to you.
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An electrical installation is fed by an effective (RMS) voltage .
It consumes power .
The frequency is and effective (RMS) intensity .
Knowing that this installation is of the inductive type, calculate the resistance and inductance which, placed in series and with the same supply, would be equivalent to the installation.
We can write the equations :
We can deduce :
Calculate the capacitance to place in parallel to the installation to meet the power factor value .
Equivalent admittance is calculated, in complex notation :
Can be calculated :
Then the value of :
With , it comes :